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Find the area between y = x^2+ 3x - 8 and y = 3x - 8 over the interval (sqrt(41)-3) / 2 <= x <= 8/3
Find the area between y = x^2+ 3x - 8 and y = 3x - 8 over the interval (sqrt(41)-3) / 2 <= x <= 8/3
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