解 \begincases x + 2y - z = 1 }, {2x + 4y - 2z = 2 }, {x + y + z = 3 \endcases ——注意冗余。解 \begincases x + 2y - z = 1 }, {2x + 4y - 2z = 2 }, {x + y + z = 3 \endcases ——注意冗余。

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