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代数证明 S^2 = (1)/(n-1)sum (X_i - \bar X)^2 是 的无偏估计量。为什么分母是 而不是 ?
代数证明 S^2 = (1)/(n-1)sum (X_i - \bar X)^2 是 的无偏估计量。为什么分母是 而不是 ?
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