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从 TFC1 证明 TFC2：若 F' = f 且 f 在 [a,b] 上连续，则 integrate from a to b of f(x) dx = F(b) - F(a) 。
从 TFC1 证明 TFC2：若 F' = f 且 f 在 [a,b] 上连续，则 integrate from a to b of f(x) dx = F(b) - F(a) 。
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