2binomial(n, 5)(n/(eln(n)))^5=binomial (n, 4)(n/(eln(n)))^4+binomial (n, 6)(n/(eln(n)))^62binomial(n, 5)(n/(eln(n)))^5=binomial (n, 4)(n/(eln(n)))^4+binomial (n, 6)(n/(eln(n)))^6

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