\frac{2x+arctan y}{1-\frac{x}{1+y^2}}=\frac{-(1+y^2) (2x+arctan y)}{-1+x-y^2}\frac{2x+arctan y}{1-\frac{x}{1+y^2}}=\frac{-(1+y^2) (2x+arctan y)}{-1+x-y^2}

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