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\frac{\left(x-1\right)}{2}=\frac{\left(y+2\right)}{-3}=\frac{z-5}{4}=k,\:k=1
\frac{\left(x-1\right)}{2}=\frac{\left(y+2\right)}{-3}=\frac{z-5}{4}=k,\:k=1
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