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\frac{\frac{e^(ax) sin bx}{a}-\frac{be^(bx) cos bx}{a^2}}{1-\frac{b^2}{a^2}}
\frac{\frac{e^(ax) sin bx}{a}-\frac{be^(bx) cos bx}{a^2}}{1-\frac{b^2}{a^2}}
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