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(sum of (2^(n+1)* tan((pi/4)/(2^n)) *sin((pi/2)/(2^n))^2) from n= 0 to n = inf)
(sum of (2^(n+1)* tan((pi/4)/(2^n)) *sin((pi/2)/(2^n))^2) from n= 0 to n = inf)
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