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{p[n + 1] == (2/6) p[n] + (4/6) p[n - 1], p[0] == 1, p[1] == 2/6}
{p[n + 1] == (2/6) p[n] + (4/6) p[n - 1], p[0] == 1, p[1] == 2/6}
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