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sum ( (-1)^n sin( (2 \pi /5) (n(n+1)(2n+1)(3n^2+3n-1)/30- (3/5)n(n+1)(2n+1) ))), n=1 to 500
sum ( (-1)^n sin( (2 \pi /5) (n(n+1)(2n+1)(3n^2+3n-1)/30- (3/5)n(n+1)(2n+1) ))), n=1 to 500
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