equation of state for a van der Waals gas - Wolfram|Alpha
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Assuming the input refers to a formula | Use "van der Waals gas" as referring to physical system instead
van der Waals constant a:  
van der Waals constant b:  
molar volume:  
temperature:  

Input interpretation:

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Equation:

link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1link to /input/?i=8.3145+joules+per+mole+kelvin&lk=1
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Input values:

link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=5.46+bar+liters+squared+per+mole+squared&lk=1link to /input/?i=0.0305+liters+per+mole&lk=1link to /input/?i=0.0305+liters+per+mole&lk=1link to /input/?i=0.0305+liters+per+mole&lk=1link to /input/?i=0.0305+liters+per+mole&lk=1link to /input/?i=24.47+liters+per+mole&lk=1link to /input/?i=24.47+liters+per+mole&lk=1link to /input/?i=24.47+liters+per+mole&lk=1link to /input/?i=24.47+liters+per+mole&lk=1link to /input/?i=298.2+kelvins&lk=1link to /input/?i=298.2+kelvins&lk=1
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Result:

link to /input/?i=100.5+kilopascals&lk=1link to /input/?i=100.5+kilopascals&lk=1link to /input/?i=1005+millibars&lk=1link to /input/?i=1005+millibars&lk=1link to /input/?i=754.1+millimeters+of+mercury&lk=1link to /input/?i=754.1+millimeters+of+mercury&lk=1
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Download full output as:

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