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Abs[(a + b I) - 1] = Abs[(a + b I)^2 - 2 (a + b I) + 3], Abs[a + b I] = 2^(1/2)
Abs[(a + b I) - 1] = Abs[(a + b I)^2 - 2 (a + b I) + 3], Abs[a + b I] = 2^(1/2)
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