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\frac{1}{16}\sum\limits_{i=0}^1\sum\limits_{j=0}^1 (81-(2i/2)^2-3(2j/2)^2)
\frac{1}{16}\sum\limits_{i=0}^1\sum\limits_{j=0}^1 (81-(2i/2)^2-3(2j/2)^2)
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