(4 pi (n+1)(2n+1)(n-2)!(n^4-n^2-sin(pi n)/pi))/(sqrt(pi) (1/2(2n+1))! 16^n)(4 pi (n+1)(2n+1)(n-2)!(n^4-n^2-sin(pi n)/pi))/(sqrt(pi) (1/2(2n+1))! 16^n)

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