(1-i)^{2i} = e^{2i \ln (1-i)} = e^{2i \ln \left(\sqrt{2}e^{i(\frac{-\pi}{4})}\right)}(1-i)^{2i} = e^{2i \ln (1-i)} = e^{2i \ln \left(\sqrt{2}e^{i(\frac{-\pi}{4})}\right)}

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