Uh oh! Wolfram|Alpha doesn't run without JavaScript.
Please enable JavaScript. If you don't know how, you can find instructions
here
.
Once you've done that, refresh this page to start using Wolfram|Alpha.
( 1/3((2x+3)^(3/2))+C )' = 1/3*3/2*(2x+3)^1/2*2 = sqrt(2x+3)
( 1/3((2x+3)^(3/2))+C )' = 1/3*3/2*(2x+3)^1/2*2 = sqrt(2x+3)
Natural Language
Math Input
